Things I am thankful for…

Tanisha Pal Singh

26 Nov 2018

I am thankful for such a great teachers I have in school. I am also thankful to my parents because we visited Orlando Disneyworld and universal studios and also Miami in our Thanksgiving holidays.

This picture includes me and my parents doing a ride. I am the one in the red jacket.

Study guide eportfolio

Tanisha Pal Singh

7 Nov 18

Trigonometric ratios

We have been given theta as 57, adjacent as 6 and opposite as x. We have to find out the x. So we will have to think of a trigonometric ratio in which opposite and adjacent comes.

Tan 57= x÷ 6

1.539= x=÷6

X=1.539×6

X= 9.234 is the opposite.

Inverse trigonometry ratio –

We have to find out the theta which will be x, we have been given hypotenuse as 24 and opposite as 15. So- Sin x= 15÷24

Sin x= 0.625

X= 38.628

MAJOR GRADE E- PORTFOLIO

TANISHA PAL SINGH

10 GRADE

ADVANCE GEOMETRY

  1. ROTATION- 90 COUNTERCLOCKWISE- (4,-1) Rule for 90 Counterclockwise= (x ,y)- (-y , x)= We will flip the x and y= (-1, 4) and then multiply -1 by -1 which will be 1 and x will remain the same=( 1, 4) is the answer.

2) LINEAR MEASURE- FIND BD IF BC= 16.8 mm AND CD= 50.4 mm. ANSWER- BC = 16.8 mm and CD= 50.4mm then BD= 16.8mm + 50.4mm= 67.2mm

3) DISTANCE- FIND THE DISTANCE BETWEEN L( -7 , 0) AND Y (5, 9)

Answer- Formula to find distance- √( X2 – X1) + ( Y2 – Y1)

√( 5- (-7) + ( 9-0)=√( 12+9) = √21

4) REFLECTION- REFLECTION OVER Y= X

RULE = FLIP X AND Y= (X ,Y)= ( Y, X)

(-3, 0)= (0, -3) , (-4, 5)= (5, -4) , (-7, 5)= (5, -7) , (-6,6)= (6, -6)

rotations

LINEAR MEASURE

DISTANCE

REFLECTION